4x^2-20x+28=4

Solution for 4x^2-20x+28=4 equation:

Simplifying
4x2 + -20x + 28 = 4

Reorder the terms:
28 + -20x + 4x2 = 4

Solving
28 + -20x + 4x2 = 4

Solving for variable 'x'.

Reorder the terms:
28 + -4 + -20x + 4x2 = 4 + -4

Combine like terms: 28 + -4 = 24
24 + -20x + 4x2 = 4 + -4

Combine like terms: 4 + -4 = 0
24 + -20x + 4x2 = 0

Factor out the Greatest Common Factor (GCF), '4'.
4(6 + -5x + x2) = 0

Factor a trinomial.
4((2 + -1x)(3 + -1x)) = 0

Ignore the factor 4.
Subproblem 1
Set the factor '(2 + -1x)' equal to zero and attempt to solve:

Simplifying
2 + -1x = 0

Solving
2 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1x = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1x = 0 + -2
-1x = 0 + -2

Combine like terms: 0 + -2 = -2
-1x = -2

Divide each side by '-1'.
x = 2

Simplifying
x = 2
Subproblem 2
Set the factor '(3 + -1x)' equal to zero and attempt to solve:

Simplifying
3 + -1x = 0

Solving
3 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1x = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1x = 0 + -3
-1x = 0 + -3

Combine like terms: 0 + -3 = -3
-1x = -3

Divide each side by '-1'.
x = 3

Simplifying
x = 3
Solution
x = {2, 3}